The thioester (-S-C=O) acts as the ketone for an aldol reaction. This reaction starts with a protonated group acting as the electron puller on the thioester and another base simultaneously helping to remove a proton from the "other end" of the acetyl group
The results of the previous step are shown. The thioester looks kind of like an "ENOL" group intermediate and there is C=C double bond. - Now the electron flow reverses the ENOL collapses and one pair of electrons from the C=C double bond can attack the ketone of the oxaloacetate. This attack forces one pair of electrons from that ketone to move out. it can grab a proton now from a nearby acid group.
The results of the previous step are shown. The "new" C-C between the acetate and oxaloacetate has formed. The thioesters is back to an thioester and what was the ketone on the oxaloacetate is now an alcohol. This intermediate (citryl-CoA) is stable. Theoretically it can diffuse out of the active site. - but the hydrolysis steps occur very quickly
HydrolysisThe hydrolysis of the citryl-CoA begins. A base removes a proton from water generating a HO- near the thioester. This attacks C=O part of the thioester driving a pair of electrons onto the sulfur atom and cleaving the C-S bond.
The results of the previous step is shown. The C-S bond is broken. Citrate has formed and there is a negative charge on the sulfur. The S- will pick up a proton from any source, preferably a nearby acid group.
the reaction is complete. CoASH and citrate are the final products.
Reaction | Rationale | Thermodynamics | Mechanism | Pictures | JMOL |
Enzyme Name |
Citrate Synthase |
|
|
||
Reaction Catalyzed |
two step reaction:
|
|
Reaction Type |
Two Step Reaction
|
|
Pathway Involvement |
Citric Acid Cycle |
|
Cofactors/Cosubstrates |
Coenzyme A is a product of the hydrolysis that follows the aldol reaction |